An object undergoing simple harmonic motion 0.25 s to travel from one point of zero velcocity to the next such point. The distance between those points is 36 cm. Calculate (A) the period (b) the frequency (c) the amplitude fo the motion.
What is the answer no one can find it to all three a b and c?
Period is the time to come again to the initial position.
Period = 2 x 0.25 s = 0.5 second.
Frequency is the number of oscillations per second.
Inverse of period = 1/ T = 1/ 0.5 = 2 Hz.
Or
In 0.5 second it completes one oscillation.
In another 0.5 s it will complete another oscillation.
Therefore, in one second it completes two oscillations.
The frequency is 2 per second.
Amplitude is half of the given length = 18cm.
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